Ruka hadi maudhui
The Lumenary
Shahada ya kwanza (mwanzo)NumberImepangwa

Congruences

Congruence modulo n as an equivalence relation compatible with addition and multiplication; linear congruences, inverses modulo n, the Chinese remainder theorem, and the theorems of Fermat, Euler and Wilson.

math.number.congruences

Somo la mada hii bado halijaandikwa. Muhtasari ulio hapa chini ni sehemu ya ramani ya mtaala na haujakaguliwa.

Inajengwa juu ya

Masharti ya awali ya lazima 13 (hadi chini kabisa)

Utajifunza

  • Prove that congruence modulo n is an equivalence relation compatible with + and ×.
  • Solve linear congruences ax ≡ b (mod n) and systems of congruences using the Chinese remainder theorem.
  • Prove Fermat's little theorem and Euler's theorem and use them to compute large powers modulo n.

Fasili

  • a ≡ b (mod n) means that n divides a − b.
  • Euler's totient φ(n) is the number of integers in {1, …, n} that are coprime to n.
  • An inverse of a modulo n is an integer b with ab ≡ 1 (mod n).

Nadharia

  • a has an inverse modulo n if and only if gcd(a, n) = 1.
  • Chinese remainder theorem: if m and n are coprime, the system x ≡ a (mod m), x ≡ b (mod n) has a solution, unique modulo mn.
  • Fermat: if p is prime and p does not divide a, then a^(p−1) ≡ 1 (mod p).
  • Euler: if gcd(a, n) = 1 then a^φ(n) ≡ 1 (mod n).
  • Wilson: (p − 1)! ≡ −1 (mod p) for every prime p.

Mawazo potofu ya kawaida

  • Cancelling a factor that is not coprime to n: 2 · 3 ≡ 2 · 9 (mod 12), but 3 ≢ 9 (mod 12).
  • Assuming the converse of Fermat's theorem: the Carmichael number 561 = 3 · 11 · 17 satisfies a^560 ≡ 1 (mod 561) for every a coprime to 561.

Inaelekea kwa

Ugunduzi wa hiari

Usomaji zaidi

  • Kenneth Ireland and Michael Rosen, A Classical Introduction to Modern Number Theory
  • Carl Friedrich Gauss, Disquisitiones Arithmeticae (1801)